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D 3 Y D X 3 + D 2 Y D X 2 + D Y D X + Y Sin Y = 0 - Mathematics

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प्रश्न

\[\frac{d^3 y}{d x^3} + \frac{d^2 y}{d x^2} + \frac{dy}{dx} + y \sin y = 0\]
योग
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उत्तर

\[\frac{d^3 y}{d x^3} + \frac{d^2 y}{d x^2} + \frac{dy}{dx} + y \sin y = 0\]

In this differential equation, the order of the highest order derivative is 3 and its power is 1. So, the order of the differential equation is 3 and its degree is 1.

It is a non-linear differential equation, as the exponent of the dependent variable is not equal to 1 (by expanding \[y . \sin y\]).

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Notes

The answer given in the book has some error. The solution here is created according to the question given in the book.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 22: Differential Equations - Exercise 22.01 [पृष्ठ ५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 22 Differential Equations
Exercise 22.01 | Q 24 | पृष्ठ ५

वीडियो ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्न

Order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively 

(A) 2, 3

(B) 3, 2

(C) 7, 2

(D) 3, 7


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Fill in the blank:

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Select and write the correct alternative from the given option for the question

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