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प्रश्न
Determine the order and degree of the following differential equation:
`("d"^2"y")/"dx"^2 + ("dy"/"dx")^2 + 7"x" + 5 = 0`
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उत्तर
The given D.E. is
`("d"^2"y")/"dx"^2 + ("dy"/"dx")^2 + 7"x" + 5 = 0`
This D.E. has highest order derivative `("d"^2"y")/"dx"^2` with power 1.
∴ the given D.E. has order 2 and degree 1.
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