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Find the general solution of the following differential equation: dydx=ex-y+x2e-y - Mathematics

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प्रश्न

Find the general solution of the following differential equation:

`(dy)/(dx) = e^(x-y) + x^2e^-y`

योग
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उत्तर

Given differential equation is `(dy)/(dx) = e^(x-y) + x^2e^-y`

⇒ `(dy)/(dx) = e^-y(e^x + x^2)`

⇒ `(dy)/e^-y = dx(e^x + x^2)`

⇒ `e^ydy = e^xdx + x^2dx`

On integrating both sides, we get

`e^y = e^x + x^3/3 + c`

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2021-2022 (March) Term 2 - Delhi Set 1

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