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For the differential equation given below, indicate its order and degree (if defined). d2ydx2+5x(dydx)2-6y=logx - Mathematics

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प्रश्न

For the differential equation given below, indicate its order and degree (if defined).

`(d^2y)/dx^2 + 5x(dy/dx)^2 - 6y = log x`

योग
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उत्तर

`(d^2y)/dx^2 + 5x(dy/dx)^2 - 6y = log x`

In this differential equation, the highest derivative order is `(d^2y)/dx^2.`

Therefore, the order of the equation is 2, and the Degree is 1.

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अध्याय 9: Differential Equations - Exercise 9.7 [पृष्ठ ४१९]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 9 Differential Equations
Exercise 9.7 | Q 1.1 | पृष्ठ ४१९

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