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Determine the order and degree of the following differential equation: dydxdydx(dydx)23=d2ydx2

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प्रश्न

Determine the order and degree of the following differential equation:

`root(3)(1 +("dy"/"dx")^2) = ("d"^2"y")/"dx"^2`

योग
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उत्तर

The given D.E. is

`root(3)(1 +("dy"/"dx")^2) = ("d"^2"y")/"dx"^2`

On cubing both sides, we get

`1 +("dy"/"dx")^2 = (("d"^2"y")/"dx"^2)^3`

This D.E. has highest order derivative `("d"^2"y")/"dx"^2` with power 3.

∴ the given D.E. is of order 2 and degree 3.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Differential Equations - Exercise 6.1 [पृष्ठ १९३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Exercise 6.1 | Q 2 | पृष्ठ १९३
बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Miscellaneous exercise 2 | Q 1.3 | पृष्ठ २१६

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