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Determine the order and degree (if defined) of the differential equation: d2y(dx2)2+cos(dydx)=0 - Mathematics

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प्रश्न

Determine the order and degree (if defined) of the differential equation:

`(d^2y)/(dx^2)^2 + cos(dy/dx) = 0`

संक्षेप में उत्तर
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उत्तर

`(d^2y)/(dx^2)^2 + cos(dy/dx) = 0`

The highest order derivative present in the given differential equation is `(d^2y)/(dx^2)`.

Therefore, its order is 2.

The given differential equation is not a polynomial equation in its derivatives. Hence, its degree is not defined.

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अध्याय 9: Differential Equations - Exercise 9.1 [पृष्ठ ३८२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 9 Differential Equations
Exercise 9.1 | Q 4 | पृष्ठ ३८२

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