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S 2 D 2 T D S 2 + S T D T D S = S

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प्रश्न

\[s^2 \frac{d^2 t}{d s^2} + st\frac{dt}{ds} = s\]
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उत्तर

\[s^2 \frac{d^2 t}{d s^2} + st\frac{dt}{ds} = s\]

\[ \Rightarrow s\frac{d^2 t}{d s^2} + t\frac{dt}{ds} = 1\]

In this differential equation, the order of the highest order derivative is 2 and its power is 1. So, it is a differential equation of order 2 and degree 1.

It is a non-linear differential equation, as it contains the product of the dependent variable \[\left( t \right)\]  and its differential co-efficient \[\left( \frac{dt}{ds} \right)\].

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अध्याय 21: Differential Equations - Exercise 22.01 [पृष्ठ ५]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
Exercise 22.01 | Q 10 | पृष्ठ ५

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