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The Degree of the Differential Equation { 5 + ( D Y D X ) 2 } 5 / 3 = X 5 ( D 2 Y D X 2 ) , is

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प्रश्न

The degree of the differential equation \[\left\{ 5 + \left( \frac{dy}{dx} \right)^2 \right\}^{5/3} = x^5 \left( \frac{d^2 y}{d x^2} \right)\], is

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MCQ
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उत्तर

3

 

We have,
\[\left[ 5 + \left( \frac{dy}{dx} \right)^2 \right]^\frac{5}{3} = x^5 \left( \frac{d^2 y}{d^2 x} \right)\]
Taking Cube power on both sides, we get
\[ \left( 5 + \left( \frac{dy}{dx} \right)^2 \right)^5 = x^{15} \left( \frac{d^2 y}{d^2 x} \right)^3 \]
\[\text{ The highest order derivative is }\frac{d^2 y}{d^2 x}\text{ and its power is 3 . }\]
Hence, the degree is 3.

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अध्याय 21: Differential Equations - MCQ [पृष्ठ १४०]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
MCQ | Q 5 | पृष्ठ १४०

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