हिंदी

The order and degree of the differential equation [1+(dydx)2]=d2ydx2 are ______.

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प्रश्न

The order and degree of the differential equation `[1 + ((dy)/(dx))^2] = (d^2y)/(dx^2)` are ______.

विकल्प

  • `2, 3/2`

  • 2, 3

  • 2, 1

  • 3, 4

MCQ
रिक्त स्थान भरें
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उत्तर

The order and degree of the differential equation `[1 + ((dy)/(dx))^2] = (d^2y)/(dx^2)` are 2, 1.

Explanation:

The given differential equation is `1 + ((dy)/(dx))^2 = (d^2y)/(dx^2)`

Here, the highest derivative is 2

∴ Order = 2 and the power of the highest derivative is 1.

∴ Degree = 1.

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अध्याय 9: Differential Equations - Exercise [पृष्ठ २००]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 68 | पृष्ठ २००

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