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प्रश्न
The order and degree of the differential equation `("d"^2y)/("d"x^2) + (("d"y)/("d"x))^(1/4) + x^(1/5)` = 0, respectively, are ______.
विकल्प
2 and not defined
2 and 2
2 and 3
3 and 3
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उत्तर
The order and degree of the differential equation `("d"^2y)/("d"x^2) + (("d"y)/("d"x))^(1/4) + x^(1/5)` = 0, respectively, are 2 and not defined.
Explanation:
Given differential equation is
`("d"^2y)/("d"x^2) + (("d"y)/("d"x))^(1/4) + x^(1/5)` = 0
⇒ `("d"^2y)/("d"x^2) + (("d"y)/("d"x))^(1/4) = - x^(1/5)`
Since the degree of `("d"y)/("d"x)` is in fraction.
So, the degree of the differential equation is not defined as the order is 2.
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