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Determine the order and degree (if defined) of the differential equation: (dsdt)4+3s d2sdt2=0 - Mathematics

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Question

Determine the order and degree (if defined) of the differential equation:

`((ds)/(dt))^4 + 3s  (d^2s)/(dt^2) = 0`

Answer in Brief
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Solution

`((ds)/(dt))^4 + 3s  (d^2s)/(dt^2) = 0`

The highest order derivative present in the given differential equation is `(d^2s)/(dt)^2`. Therefore, 

It is a polynomial equation in `(d^2s)/(dt^2)and (ds)/(dt)`. The power raised to `(d^2s)/(dt^2)` is 1

Hence, its degree is one.

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Chapter 9: Differential Equations - Exercise 9.1 [Page 382]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 9 Differential Equations
Exercise 9.1 | Q 3 | Page 382

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