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प्रश्न
Determine the order and degree (if defined) of the differential equation:
`((ds)/(dt))^4 + 3s (d^2s)/(dt^2) = 0`
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उत्तर
`((ds)/(dt))^4 + 3s (d^2s)/(dt^2) = 0`
The highest order derivative present in the given differential equation is `(d^2s)/(dt)^2`. Therefore,
It is a polynomial equation in `(d^2s)/(dt^2)and (ds)/(dt)`. The power raised to `(d^2s)/(dt^2)` is 1
Hence, its degree is one.
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