English

D Y D X = X 5 + X 2 − 2 X , X ≠ 0

Advertisements
Advertisements

Question

\[\frac{dy}{dx} = x^5 + x^2 - \frac{2}{x}, x \neq 0\]
Sum
Advertisements

Solution

We have,
\[\frac{dy}{dx} = x^5 + x^2 - \frac{2}{x}\]
\[ \Rightarrow dy = \left( x^5 + x^2 - \frac{2}{x} \right)dx\]
Integrating both sides, we get
\[ \Rightarrow \int dy = \int\left( x^5 + x^2 - \frac{2}{x} \right)dx\]
\[ \Rightarrow y = \frac{x^6}{6} + \frac{x^3}{3} - 2\log\left| x \right| + C\]
\[\text{Clearly, } y = \frac{x^6}{6} + \frac{x^3}{3} - 2\log\left| x \right| + \text{ C is defined for all }x \in R \text{ except }x = 0 . \]
\[\text{ Hence, }y = \frac{x^6}{6} + \frac{x^3}{3} - 2\log\left| x \right| + \text{ C, where } x \in R - \left\{ 0 \right\}, \text{ is the solution to the given differential equation.}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 21: Differential Equations - Exercise 22.05 [Page 34]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 21 Differential Equations
Exercise 22.05 | Q 2 | Page 34

RELATED QUESTIONS

\[x^2 \left( \frac{d^2 y}{d x^2} \right)^3 + y \left( \frac{dy}{dx} \right)^4 + y^4 = 0\]

Verify that y = 4 sin 3x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + 9y = 0\]


\[\left( x + 2 \right)\frac{dy}{dx} = x^2 + 3x + 7\]

\[\frac{dy}{dx} = x \log x\]

\[\frac{dy}{dx} + \frac{1 + y^2}{y} = 0\]

(1 + x2) dy = xy dx


Solve the differential equation \[\frac{dy}{dx} = e^{x + y} + x^2 e^y\].

\[x\frac{dy}{dx} + y = y^2\]

(ey + 1) cos x dx + ey sin x dy = 0


(1 − x2) dy + xy dx = xy2 dx


y (1 + ex) dy = (y + 1) ex dx


\[\left( x - 1 \right)\frac{dy}{dx} = 2 x^3 y\]

\[\frac{dy}{dx} = e^{x + y} + e^{- x + y}\]

Solve the following differential equation:
\[xy\frac{dy}{dx} = 1 + x + y + xy\]

 


\[\frac{dy}{dx} = y \tan 2x, y\left( 0 \right) = 2\] 

\[xy\frac{dy}{dx} = \left( x + 2 \right)\left( y + 2 \right), y\left( 1 \right) = - 1\]

The volume of a spherical balloon being inflated changes at a constant rate. If initially its radius is 3 units and after 3 seconds it is 6 units. Find the radius of the balloon after `t` seconds.


x2 dy + y (x + y) dx = 0


Solve the following initial value problem:-
\[x\frac{dy}{dx} - y = \log x, y\left( 1 \right) = 0\]


Solve the following initial value problem:-

\[x\frac{dy}{dx} - y = \left( x + 1 \right) e^{- x} , y\left( 1 \right) = 0\]


Solve the following initial value problem:-

\[\left( 1 + y^2 \right) dx + \left( x - e^{- \tan^{- 1} y} \right) dx = 0, y\left( 0 \right) = 0\]


Solve the following initial value problem:-
\[\tan x\left( \frac{dy}{dx} \right) = 2x\tan x + x^2 - y; \tan x \neq 0\] given that y = 0 when \[x = \frac{\pi}{2}\]


A population grows at the rate of 5% per year. How long does it take for the population to double?


Find the equation of the curve passing through the point \[\left( 1, \frac{\pi}{4} \right)\]  and tangent at any point of which makes an angle tan−1  \[\left( \frac{y}{x} - \cos^2 \frac{y}{x} \right)\] with x-axis.


A curve is such that the length of the perpendicular from the origin on the tangent at any point P of the curve is equal to the abscissa of P. Prove that the differential equation of the curve is \[y^2 - 2xy\frac{dy}{dx} - x^2 = 0\], and hence find the curve.


Write the differential equation representing the family of straight lines y = Cx + 5, where C is an arbitrary constant.


Find the solution of the differential equation
\[x\sqrt{1 + y^2}dx + y\sqrt{1 + x^2}dy = 0\]


The solution of the differential equation \[\frac{dy}{dx} = \frac{ax + g}{by + f}\] represents a circle when


Solve the following differential equation : \[\left( \sqrt{1 + x^2 + y^2 + x^2 y^2} \right) dx + xy \ dy = 0\].


Solve the following differential equation.

`x^2 dy/dx = x^2 +xy - y^2`


Solve the following differential equation.

`dy/dx + 2xy = x`


The solution of `dy/ dx` = 1 is ______.


Solve:

(x + y) dy = a2 dx


Select and write the correct alternative from the given option for the question 

Differential equation of the function c + 4yx = 0 is


Solve `("d"y)/("d"x) = (x + y + 1)/(x + y - 1)` when x = `2/3`, y = `1/3`


For the differential equation, find the particular solution

`("d"y)/("d"x)` = (4x +y + 1), when y = 1, x = 0


Solve the following differential equation

`x^2  ("d"y)/("d"x)` = x2 + xy − y2 


Choose the correct alternative:

Differential equation of the function c + 4yx = 0 is


Solve the following differential equation 

sec2 x tan y dx + sec2 y tan x dy = 0

Solution: sec2 x tan y dx + sec2 y tan x dy = 0

∴ `(sec^2x)/tanx  "d"x + square` = 0

Integrating, we get

`square + int (sec^2y)/tany  "d"y` = log c

Each of these integral is of the type

`int ("f'"(x))/("f"(x))  "d"x` = log |f(x)| + log c

∴ the general solution is

`square + log |tan y|` = log c

∴ log |tan x . tan y| = log c

`square`

This is the general solution.


Solve the differential equation

`x + y dy/dx` = x2 + y2


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×