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D Y D X = X 5 + X 2 − 2 X , X ≠ 0

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प्रश्न

\[\frac{dy}{dx} = x^5 + x^2 - \frac{2}{x}, x \neq 0\]
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उत्तर

We have,
\[\frac{dy}{dx} = x^5 + x^2 - \frac{2}{x}\]
\[ \Rightarrow dy = \left( x^5 + x^2 - \frac{2}{x} \right)dx\]
Integrating both sides, we get
\[ \Rightarrow \int dy = \int\left( x^5 + x^2 - \frac{2}{x} \right)dx\]
\[ \Rightarrow y = \frac{x^6}{6} + \frac{x^3}{3} - 2\log\left| x \right| + C\]
\[\text{Clearly, } y = \frac{x^6}{6} + \frac{x^3}{3} - 2\log\left| x \right| + \text{ C is defined for all }x \in R \text{ except }x = 0 . \]
\[\text{ Hence, }y = \frac{x^6}{6} + \frac{x^3}{3} - 2\log\left| x \right| + \text{ C, where } x \in R - \left\{ 0 \right\}, \text{ is the solution to the given differential equation.}\]

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अध्याय 21: Differential Equations - Exercise 22.05 [पृष्ठ ३४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
Exercise 22.05 | Q 2 | पृष्ठ ३४

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