हिंदी

Select and write the correct alternative from the given option for the question Differential equation of the function c + 4yx = 0 is - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Select and write the correct alternative from the given option for the question 

Differential equation of the function c + 4yx = 0 is

विकल्प

  • `xy + ("d"y)/("d"x)` = 0

  • `x  ("d"y)/("d"x) + y` = 0

  • `("d"y)/("d"x) - 4xy` = 0

  • `x ("d"y)/("d"x) + 1` = 0

MCQ
Advertisements

उत्तर

`x ("d"y)/("d"x) + y` = 0

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2.6: Differential Equations - MCQ

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

\[\frac{d^3 x}{d t^3} + \frac{d^2 x}{d t^2} + \left( \frac{dx}{dt} \right)^2 = e^t\]

\[\frac{d^2 y}{d x^2} + \left( \frac{dy}{dx} \right)^2 + xy = 0\]

\[\frac{d^4 y}{d x^4} = \left\{ c + \left( \frac{dy}{dx} \right)^2 \right\}^{3/2}\]

\[x^2 \left( \frac{d^2 y}{d x^2} \right)^3 + y \left( \frac{dy}{dx} \right)^4 + y^4 = 0\]

Form the differential equation of the family of hyperbolas having foci on x-axis and centre at the origin.


Show that y = AeBx is a solution of the differential equation

\[\frac{d^2 y}{d x^2} = \frac{1}{y} \left( \frac{dy}{dx} \right)^2\]

Verify that \[y = ce^{tan^{- 1}} x\]  is a solution of the differential equation \[\left( 1 + x^2 \right)\frac{d^2 y}{d x^2} + \left( 2x - 1 \right)\frac{dy}{dx} = 0\]


Differential equation \[\frac{d^2 y}{d x^2} - \frac{dy}{dx} = 0, y \left( 0 \right) = 2, y'\left( 0 \right) = 1\]

Function y = ex + 1


\[x\frac{dy}{dx} + 1 = 0 ; y \left( - 1 \right) = 0\]

\[\frac{dy}{dx} + \frac{1 + y^2}{y} = 0\]

\[\frac{dy}{dx} = \left( e^x + 1 \right) y\]

xy dy = (y − 1) (x + 1) dx


\[\sqrt{1 + x^2} dy + \sqrt{1 + y^2} dx = 0\]

\[\frac{dy}{dx} + \frac{\cos x \sin y}{\cos y} = 0\]

\[\left( x - 1 \right)\frac{dy}{dx} = 2 x^3 y\]

\[2x\frac{dy}{dx} = 3y, y\left( 1 \right) = 2\]

\[2x\frac{dy}{dx} = 5y, y\left( 1 \right) = 1\]

\[\frac{dy}{dx} = 2 e^{2x} y^2 , y\left( 0 \right) = - 1\]

\[\frac{dy}{dx} = \left( x + y + 1 \right)^2\]

\[\cos^2 \left( x - 2y \right) = 1 - 2\frac{dy}{dx}\]

\[\frac{dy}{dx} = \frac{x + y}{x - y}\]

\[2xy\frac{dy}{dx} = x^2 + y^2\]

y ex/y dx = (xex/y + y) dy


(y2 − 2xy) dx = (x2 − 2xy) dy


\[\frac{dy}{dx} = \frac{y}{x} - \sqrt{\frac{y^2}{x^2} - 1}\]

Experiments show that radium disintegrates at a rate proportional to the amount of radium present at the moment. Its half-life is 1590 years. What percentage will disappear in one year?


The normal to a given curve at each point (x, y) on the curve passes through the point (3, 0). If the curve contains the point (3, 4), find its equation.


Write the differential equation obtained by eliminating the arbitrary constant C in the equation x2 − y2 = C2.


The differential equation obtained on eliminating A and B from y = A cos ωt + B sin ωt, is


The differential equation \[x\frac{dy}{dx} - y = x^2\], has the general solution


Solve the following differential equation : \[y^2 dx + \left( x^2 - xy + y^2 \right)dy = 0\] .


Find the equation of the plane passing through the point (1, -2, 1) and perpendicular to the line joining the points A(3, 2, 1) and B(1, 4, 2). 


Solve the following differential equation.

`dy/dx = x^2 y + y`


For each of the following differential equations find the particular solution.

(x − y2 x) dx − (y + x2 y) dy = 0, when x = 2, y = 0


Solve the following differential equation.

(x2 − y2 ) dx + 2xy dy = 0


A solution of a differential equation which can be obtained from the general solution by giving particular values to the arbitrary constants is called ___________ solution.


The integrating factor of the differential equation `dy/dx - y = x` is e−x.


 `dy/dx = log x`


Select and write the correct alternative from the given option for the question

The differential equation of y = Ae5x + Be–5x is


Solve the differential equation xdx + 2ydy = 0


Choose the correct alternative:

Solution of the equation `x("d"y)/("d"x)` = y log y is


Solve the following differential equation

`y log y ("d"x)/("d"y) + x` = log y


Solve `x^2 "dy"/"dx" - xy = 1 + cos(y/x)`, x ≠ 0 and x = 1, y = `pi/2`


Given that `"dy"/"dx" = "e"^-2x` and y = 0 when x = 5. Find the value of x when y = 3.


The differential equation of all non horizontal lines in a plane is `("d"^2x)/("d"y^2)` = 0


If `y = log_2 log_2(x)` then `(dy)/(dx)` =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×