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Question
Construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm respectively. Find by construction a point P equidistant from AB and AD and also from C and D.
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Solution
Steps of Construction:
(i) Draw BC = 6 cm.
(ii) Draw AD = 8 on perpendicular to BC.
(iii) With B as centre draw arcs on AD.
(iv) With C as centre draw arcs on AD. ABCD is the required rhombus.
(v) Draw perpendicular bisectors of AB, and CD, which meet at 0.
(vi) Since AD and BC are diagonals of rhombus and meet at 0.
AO = OD
O is the point equidistant from AB, AD and C, D.
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