English

Construct a Rhombus Abcd with Sides of Length 5 Cm and Diagonal Ac of Length 6 Cm

Advertisements
Advertisements

Question

Construct a rhombus ABCD with sides of length 5 cm and diagonal AC of length 6 cm. Measure ∠ ABC. Find the point R on AD such that RB = RC. Measure the length of AR. 

Diagram
Advertisements

Solution

Steps of Construction: 

(i) Draw AC= 6 cm. 

(ii) With A as centre, draw two arcs of 5 cm on both sides of line AC. 

(iii) With C as centre, draw two arcs of 5 cm on both sides of line AC. 

(iv) All the arcs meet at Band D. Join AB, AD, BC and BD. ABCD is the required rhombus. 

(v) On measuring, ∠ ABC = 78>. 

(vi) Draw perpendicular bisector of BC meeting AD at R. R is the pdnt equidistant from Band C, hence RB = RC. 

(vii) On measuring, R = 1.2 cm 

shaalaa.com
  Is there an error in this question or solution?
Chapter 15: Loci - Exercise 16.1

APPEARS IN

Frank Mathematics Part 2 [English] Class 10 ICSE
Chapter 15 Loci
Exercise 16.1 | Q 6

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Describe the locus of a point in space, which is always at a distance of 4 cm from a fixed point.  


Describe the locus of a point P, so that:

AB2 = AP2 + BP2,

where A and B are two fixed points.


Ruler and compasses may be used in this question. All construction lines and arcs must be clearly shown and be of sufficient length and clarity to permit assessment.

  1. Construct a ΔABC, in which BC = 6 cm, AB = 9 cm and angle ABC = 60°.
  2. Construct the locus of all points inside triangle ABC, which are equidistant from B and C.
  3. Construct the locus of the vertices of the triangles with BC as base and which are equal in area to triangle ABC.
  4. Mark the point Q, in your construction, which would make ΔQBC equal in area to ΔABC, and isosceles.
  5. Measure and record the length of CQ.

Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB. 


In the given figure ABC is a triangle. CP bisects angle ACB and MN is perpendicular bisector of BC. MN cuts CP at Q. Prove Q is equidistant from B and C, and also that Q is equidistant from BC and AC. 


Describe completely the locus of a point in the following case:

Centre of a ball, rolling along a straight line on a level floor. 


Describe completely the locus of a point in the following case:

Point in a plane equidistant from a given line. 


Construct a Δ ABC, with AB = 6 cm, AC = BC = 9 cm; find a point 4 cm from A and equidistant from B and C.


Using ruler and compasses construct:
(i) a triangle ABC in which AB = 5.5 cm, BC = 3.4 cm and CA = 4.9 cm.
(ii) the locus of point equidistant from A and C.
(iii) a circle touching AB at A and passing through C.


Given ∠BAC (Fig), determine the locus of a point which lies in the interior of ∠BAC and equidistant from two lines AB and AC.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×