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प्रश्न
Construct a rhombus ABCD with sides of length 5 cm and diagonal AC of length 6 cm. Measure ∠ ABC. Find the point R on AD such that RB = RC. Measure the length of AR.
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उत्तर
Steps of Construction:
(i) Draw AC= 6 cm.
(ii) With A as centre, draw two arcs of 5 cm on both sides of line AC.
(iii) With C as centre, draw two arcs of 5 cm on both sides of line AC.
(iv) All the arcs meet at Band D. Join AB, AD, BC and BD. ABCD is the required rhombus.
(v) On measuring, ∠ ABC = 78>.
(vi) Draw perpendicular bisector of BC meeting AD at R. R is the pdnt equidistant from Band C, hence RB = RC.
(vii) On measuring, R = 1.2 cm
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संबंधित प्रश्न
Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:
- equidistant from BA and BC.
- 4 cm from M.
- 4 cm from N.
Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Join MP and NP, and describe the figure BMPN.
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(ii) Construct the locus of points, inside the circle that are equidistant from AB and AC.
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The Iocus of the mid-points of all parallel chords of a circle.
Describe completely the locus of a point in the following case:
Point in a plane equidistant from a given line.
Without using set squares or protractor construct a triangle ABC in which AB = 4 cm, BC = 5 cm and ∠ABC = 120°.
(i) Locate the point P such that ∠BAp = 90° and BP = CP.
(ii) Measure the length of BP.
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Using ruler and compasses construct:
(i) a triangle ABC in which AB = 5.5 cm, BC = 3.4 cm and CA = 4.9 cm.
(ii) the locus of point equidistant from A and C.
(iii) a circle touching AB at A and passing through C.
