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प्रश्न
Construct a Δ XYZ in which XY= 4 cm, YZ = 5 cm and ∠ Y = 1200. Locate a point T such that ∠ YXT is a right angle and Tis equidistant from Y and Z. Measure TZ.
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उत्तर
Steps of Construction:
(i) Draw YZ = 5 cm
(ii) Draw an arc with angle Y= 120 ° and radius 4 cm.
(iii) Join XZ.
(iv) Draw perpendicular bisector of YZ.
(v) With X as centre and angle X as 90° , join X to the perpendicular bisectcr at T. T is the required point.
(vi) Measure TY. TY = 6.8 cm = TZ as T lies on perpendicular bisector of YZ.
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संबंधित प्रश्न
Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm and ∠BAC = 105°
Hence:
1) Construct the locus of points equidistant from BA and BC
2) Construct the locus of points equidistant from B and C.
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Without using set squares or a protractor, construct:
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- Draw the locus of a point which moves so that it is always 2.5 cm from B.
- Draw the locus of a point which moves so that it is equidistant from the sides BC and CA.
- Mark the point of intersection of the loci with the letter P and measure PC.
