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प्रश्न
Construct a ti.PQR, in which PQ=S. 5 cm, QR=3. 2 cm and PR=4.8 cm. Draw the locus of a point which moves so that it is always 2.5 cm from Q.
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उत्तर
Steps of oonstruction:
(i) Draw PQ = 5.5 cm
(ii) With P as centre and radius 4.8 cm draw an arc.
(iii) With Q as centre and radius 3.2 cm cut another arc which meets the first arc at R. Join PR and QR. PQR is the required triangle.
(iv) Draw perpendicular bisector of PR.
(v) Q as centre and radius as 2.5 cm, draw an arc which intersects the perpendicular bisector of PR at O.
O is the required point which is at a distance of 2.5 cm from Q.
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संबंधित प्रश्न
Use ruler and compasses only for this question:
I. Construct ABC, where AB = 3.5 cm, BC = 6 cm and ABC = 60o.
II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
III. Construct the locus of points inside the triangle which are equidistant from B and C.
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Using a ruler and compass only:
(i) Construct a triangle ABC with BC = 6 cm, ∠ABC = 120° and AB = 3.5 cm.
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