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प्रश्न
Construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm respectively. Find by construction a point P equidistant from AB and AD and also from C and D.
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उत्तर
Steps of Construction:
(i) Draw BC = 6 cm.
(ii) Draw AD = 8 on perpendicular to BC.
(iii) With B as centre draw arcs on AD.
(iv) With C as centre draw arcs on AD. ABCD is the required rhombus.
(v) Draw perpendicular bisectors of AB, and CD, which meet at 0.
(vi) Since AD and BC are diagonals of rhombus and meet at 0.
AO = OD
O is the point equidistant from AB, AD and C, D.
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संबंधित प्रश्न
Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:
- equidistant from BA and BC.
- 4 cm from M.
- 4 cm from N.
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