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प्रश्न
Construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm respectively. Find by construction a point P equidistant from AB and AD and also from C and D.
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उत्तर
Steps of Construction:
(i) Draw BC = 6 cm.
(ii) Draw AD = 8 on perpendicular to BC.
(iii) With B as centre draw arcs on AD.
(iv) With C as centre draw arcs on AD. ABCD is the required rhombus.
(v) Draw perpendicular bisectors of AB, and CD, which meet at 0.
(vi) Since AD and BC are diagonals of rhombus and meet at 0.
AO = OD
O is the point equidistant from AB, AD and C, D.
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संबंधित प्रश्न
Use ruler and compasses only for this question:
I. Construct ABC, where AB = 3.5 cm, BC = 6 cm and ABC = 60o.
II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
III. Construct the locus of points inside the triangle which are equidistant from B and C.
IV. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and records the length of PB.
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