हिंदी

Two Straight Roads Ab and Cd Cross Each Other at Pat an Angle of 75• .

Advertisements
Advertisements

प्रश्न

Two straight roads AB and CD cross each other at Pat an angle of 75°  . X is a stone on the road AB, 800m from P towards B. BY taking an appropriate scale draw a figure to locate the position of a pole, which is equidistant from P and X, and is also equidistant from the roads. 

योग
Advertisements

उत्तर

Steps of construction: 

(i) Draw two lines AB and CD crossing at an angle of 75 °

(ii) Draw an angle bisector for  ∠ BPD 

(iii) Draw perpendicular from X on angle bisector meeting at 0. 

(iv) From point Y, PX = PY, draw a perpendicular on angle bisector meeting at 0. 

(v) 0 is the point which is equidistant from P, X and both the roads. 

cos θ = `"hypotenuse"/"base"`

cos `75/2 = "PO"/"PX"`

cos (37.5) = `"PO"/800`

0.980243 = `"PO"/800`

PO = 784.19 m

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Loci - Exercise 16.1

APPEARS IN

फ्रैंक Mathematics Part 2 [English] Class 10 ICSE
अध्याय 15 Loci
Exercise 16.1 | Q 2

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB. 


AB and CD are two intersecting lines. Find a point equidistant from AB and CD, and also at a distance of 1.8 cm from another given line EF. 


Construct a Δ XYZ in which XY= 4 cm, YZ = 5 cm and ∠ Y = 1200. Locate a point T such that ∠ YXT is a right angle and Tis equidistant from Y and Z. Measure TZ. 


In the given figure ABC is a triangle. CP bisects angle ACB and MN is perpendicular bisector of BC. MN cuts CP at Q. Prove Q is equidistant from B and C, and also that Q is equidistant from BC and AC. 


In Δ PQR, bisectors of  ∠ PQR and ∠ PRQ meet at I. Prove that I is equidistant from the three sides of the triangle , and PI bisects ∠ QPR . 


Draw and describe the locus in the following case:

The locus of a point in rhombus ABCD which is equidistant from AB and AD.


Describe completely the locus of a point in the following case:

Point in a plane equidistant from a given line. 


Describe completely the locus of a point in the following case:

Centre of a circle of varying radius and touching the two arms of ∠ ABC. 


Use ruler and compass only for the following question. All construction lines and arcs must be clearly shown.

  1. Construct a ΔABC in which BC = 6.5 cm, ∠ABC = 60°, AB = 5 cm.
  2. Construct the locus of points at a distance of 3.5 cm from A.
  3. Construct the locus of points equidistant from AC and BC.
  4. Mark 2 points X and Y which are at a distance of 3.5 cm from A and also equidistant from AC and BC. Measure XY.

Use ruler and compasses only for the following questions:
Construct triangle BCP, when CB = 5 cm, BP = 4 cm, ∠PBC = 45°.
Complete the rectangle ABCD such that :
(i) P is equidistant from AB and BC and
(ii) P is equidistant from C and D. Measure and write down the length of AB.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×