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Draw a Straight Line Ab of 9 Cm. Draw the Locus of All Points Which Are Equidistant from a and B. Prove Your Statement.

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प्रश्न

Draw a straight line AB of 9 cm. Draw the locus of all points which are equidistant from A and B. Prove your statement. 

आकृति
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उत्तर

Steps of oonstruction: 

(i) Draw a line segment AB of 9 cm. 

(ii) Draw perpendicular bisector LM of AB. LM is the required locus. 

Proof: 

(i) Take any point on LM say P. 

(ii) Join PA and PB. 

Since, Plies on the right bisector of line AB. 

Therefore, Pis equidistant from A and B. 
i.e. PA = PB 

Hence, Perpendicular bisector of AB is the locus of all points which are equidistant from A and B. 

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अध्याय 15: Loci - Exercise 16.1

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फ्रैंक Mathematics Part 2 [English] Class 10 ICSE
अध्याय 15 Loci
Exercise 16.1 | Q 1

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Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:

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  3. 4 cm from N.
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Draw and describe the lorus in  the following cases: 

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Ruler and compasses only may be used in this question. All construction lines and arcs must be clearly shown, and be of sufficient length and clarity to permit assessment.
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(iii) Mark the point Q, in your construction, which would make ΔQBC equal in area to ΔABC, and isosceles.
(iv) Measure and record the length of CQ.


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