हिंदी

Without Using Set Squares Or Protractor Construct a Triangle Abc in Which Ab = 4 Cm, Bc = 5 Cm and ∠Abc = 120°. (I) Locate the Point P Such that ∠Bap = 90° and Bp = Cp. (Ii) Measure the Length of Bp.

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प्रश्न

Without using set squares or protractor construct a triangle ABC in which AB = 4 cm, BC = 5 cm and ∠ABC = 120°.
(i) Locate the point P such that ∠BAp = 90° and BP = CP.
(ii) Measure the length of BP.

योग
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उत्तर

(i) Draw ⊥ bisector of BC. Draw AP at A such that ∠PAB = 90°. The point of intersection P of bisector and AP is the required point.
(ii) BP = 6·5 cm.

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अध्याय 17: Loci - Figure Based Questions

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आर.एस. अग्रवाल Mathematics [English] Class 10 ICSE
अध्याय 17 Loci
Figure Based Questions | Q 2

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संबंधित प्रश्न

Describe the locus of a point P, so that:

AB2 = AP2 + BP2,

where A and B are two fixed points.


O is a fixed point. Point P moves along a fixed line AB. Q is a point on OP produced such that OP = PQ. Prove that the locus of point Q is a line parallel to AB.


State the locus of a point in a rhombus ABCD, which is equidistant

  1. from AB and AD;
  2. from the vertices A and C.

In given figure 1 ABCD is an arrowhead. AB = AD and BC = CD. Prove th at AC produced bisects BD at right angles at the point M


Draw and describe the locus in the following case:

The locus of points inside a circle and equidistant from two fixed points on the circle.


Describe completely the locus of a point in the following case:

Centre of a circle of varying radius and touching the two arms of ∠ ABC. 


Using ruler and compasses construct:
(i) a triangle ABC in which AB = 5.5 cm, BC = 3.4 cm and CA = 4.9 cm.
(ii) the locus of point equidistant from A and C.
(iii) a circle touching AB at A and passing through C.


Without using set squares or a protractor, construct:

  1. Triangle ABC, in which AB = 5.5 cm, BC = 3.2 cm and CA = 4.8 cm.
  2. Draw the locus of a point which moves so that it is always 2.5 cm from B.
  3. Draw the locus of a point which moves so that it is equidistant from the sides BC and CA.
  4. Mark the point of intersection of the loci with the letter P and measure PC.

How will you find a point equidistant from three given points A, B, C which are not in the same straight line?


Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm.

  1. Construct the locus of points equidistant from B and C.
  2. Construct the locus of points equidistant from A and B.
  3. Mark the point which satisfies both the conditions (a) and (b) as 0. Construct the locus of points keeping a fixed distance OA from the fixed point 0.
  4. Construct the locus of points which are equidistant from BA and BC.

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