हिंदी

Draw and describe the locus in the following case: The locus of points inside a circle and equidistant from two fixed points on the circle.

Advertisements
Advertisements

प्रश्न

Draw and describe the locus in the following case:

The locus of points inside a circle and equidistant from two fixed points on the circle.

आकृति
लघु उत्तरीय
Advertisements

उत्तर

The locus of the points inside the circle that are equidistant from the fixed points on the circle will be the diameter, which is the perpendicular bisector of the line joining the two fixed points on the circle. 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Loci - Exercise 16.1

APPEARS IN

फ्रैंक Mathematics Part 2 [English] Class 10 ICSE
अध्याय 16 Loci
Exercise 16.1 | Q 23.2
नूतन Mathematics [English] Class 10 ICSE
अध्याय 14 Locus
Exercise 14 | Q 2. (iii) | पृष्ठ ३०२

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Ruler and compasses may be used in this question. All construction lines and arcs must be clearly shown and be of sufficient length and clarity to permit assessment.

  1. Construct a ΔABC, in which BC = 6 cm, AB = 9 cm and angle ABC = 60°.
  2. Construct the locus of all points inside triangle ABC, which are equidistant from B and C.
  3. Construct the locus of the vertices of the triangles with BC as base and which are equal in area to triangle ABC.
  4. Mark the point Q, in your construction, which would make ΔQBC equal in area to ΔABC, and isosceles.
  5. Measure and record the length of CQ.

Plot the points A(2, 9), B(–1, 3) and C(6, 3) on graph paper. On the same graph paper draw the locus of point A so that the area of ΔABC remains the same as A moves. 


Two straight roads AB and CD cross each other at Pat an angle of 75°  . X is a stone on the road AB, 800m from P towards B. BY taking an appropriate scale draw a figure to locate the position of a pole, which is equidistant from P and X, and is also equidistant from the roads. 


In the given figure ABC is a triangle. CP bisects angle ACB and MN is perpendicular bisector of BC. MN cuts CP at Q. Prove Q is equidistant from B and C, and also that Q is equidistant from BC and AC. 


Draw and describe the lorus in  the following cases: 

The locus of points at a distance of 4 cm from a fixed line. 


Draw and describe the locus in the following case:

The locus of a point in the rhombus ABCD which is equidistant from the point  A and C.


Construct a triangle BPC given BC = 5 cm, BP = 4 cm and .

i) complete the rectangle ABCD such that:
a) P is equidistant from AB and BCV
b) P is equidistant from C and D.
ii) Measure and record the length of AB.


Use ruler and compasses only for this question. Draw a circle of radius 4 cm and mark two chords, AB and AC, of the circle of length 6 cm and 5 cm respectively.

  1. Construct the locus of points, inside the circle, that are equidistant from A and C. Prove your construction.
  2. Construct the locus of points, inside the circle, that are equidistant from AB and AC.

Ruler and compasses only may be used in this question. All construction lines and arcs must be clearly shown, and be of sufficient length and clarity to permit assessment.
(i) Construct a ΔABC, in which BC = 6 cm, AB = 9 cm and ∠ABC = 60°.
(ii) Construct the locus of the vertices of the triangles with BC as base, which are equal in area to ΔABC.
(iii) Mark the point Q, in your construction, which would make ΔQBC equal in area to ΔABC, and isosceles.
(iv) Measure and record the length of CQ.


Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm.

  1. Construct the locus of points equidistant from B and C.
  2. Construct the locus of points equidistant from A and B.
  3. Mark the point which satisfies both the conditions (a) and (b) as 0. Construct the locus of points keeping a fixed distance OA from the fixed point 0.
  4. Construct the locus of points which are equidistant from BA and BC.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×