हिंदी

Draw and Describe the Lorus in the Following Cases:

Advertisements
Advertisements

प्रश्न

Draw and describe the lorus in  the following cases: 

The locus of points at a distance of 4 cm from a fixed line. 

आकृति
Advertisements

उत्तर

The locus of points at a distance of 4 cm from fixed line AB are lines Land M which are parallel to AB. 

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Loci - Exercise 16.1

APPEARS IN

फ्रैंक Mathematics Part 2 [English] Class 10 ICSE
अध्याय 15 Loci
Exercise 16.1 | Q 23.1

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Draw an angle ABC = 75°. Find a point P such that P is at a distance of 2 cm from AB and 1.5 cm from BC.


Construct a triangle ABC, with AB = 6 cm, AC = BC = 9 cm. Find a point 4 cm from A and equidistant from B and C. 


Ruler and compasses may be used in this question. All construction lines and arcs must be clearly shown and be of sufficient length and clarity to permit assessment.

  1. Construct a ΔABC, in which BC = 6 cm, AB = 9 cm and angle ABC = 60°.
  2. Construct the locus of all points inside triangle ABC, which are equidistant from B and C.
  3. Construct the locus of the vertices of the triangles with BC as base and which are equal in area to triangle ABC.
  4. Mark the point Q, in your construction, which would make ΔQBC equal in area to ΔABC, and isosceles.
  5. Measure and record the length of CQ.

Two straight roads AB and CD cross each other at Pat an angle of 75°  . X is a stone on the road AB, 800m from P towards B. BY taking an appropriate scale draw a figure to locate the position of a pole, which is equidistant from P and X, and is also equidistant from the roads. 


Draw and describe the locus in the following case:

The locus of points inside a circle and equidistant from two fixed points on the circle.


Without using set squares or protractor construct a triangle ABC in which AB = 4 cm, BC = 5 cm and ∠ABC = 120°.
(i) Locate the point P such that ∠BAp = 90° and BP = CP.
(ii) Measure the length of BP.


State and draw the locus of a point equidistant from two given parallel lines.


Using only a ruler and compass construct ∠ABC = 120°, where AB = BC = 5 cm.
(i) Mark two points D and E which satisfy the condition that they are equidistant from both ABA and BC.
(ii) In the above figure, join AD, DC, AE and EC. Describe the figures:
(a) AECB, (b) ABD, (c) ABE.


Without using set squares or a protractor, construct:

  1. Triangle ABC, in which AB = 5.5 cm, BC = 3.2 cm and CA = 4.8 cm.
  2. Draw the locus of a point which moves so that it is always 2.5 cm from B.
  3. Draw the locus of a point which moves so that it is equidistant from the sides BC and CA.
  4. Mark the point of intersection of the loci with the letter P and measure PC.

Without using set squares or protractor.
(i) Construct a ΔABC, given BC = 4 cm, angle B = 75° and CA = 6 cm.
(ii) Find the point P such that PB = PC and P is equidistant from the side BC and BA. Measure AP.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×