हिंदी

Construct a Triangle Bpc Given Bc = 5 Cm, Bp = 4 Cm and . I) Complete the Rectangle Abcd Such That: A) P is Equidistant from Ab and Bcv B) P is Equidistant from C and D. Ii) Measu

Advertisements
Advertisements

प्रश्न

Construct a triangle BPC given BC = 5 cm, BP = 4 cm and .

i) complete the rectangle ABCD such that:
a) P is equidistant from AB and BCV
b) P is equidistant from C and D.
ii) Measure and record the length of AB.

योग
Advertisements

उत्तर

  1. i) Steps of Construction:

1) Draw a line segment BC = 5 cm

2) B as centre and radius 4 cm draw an arc at an angle of 45 degrees from BC.

3) Join PC.

4) B and C as centers, draw two perpendiculars to BC.

5) P as centre and radius PC, cut an arc on the perpendicular on C at D.

6) D as centre, draw a line parallel to BC which intersects the perpendicular on B at A.

ABCD is the required rectangle such that P is equidistant from AB and BC (since BD is angle bisector of angle B) as well as C and D.

  1. ii) On measuring AB = 5.7 cm
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Describe the locus of a point P, so that:

AB2 = AP2 + BP2,

where A and B are two fixed points.


State the locus of a point in a rhombus ABCD, which is equidistant

  1. from AB and AD;
  2. from the vertices A and C.

Use graph paper for this question. Take 2 cm = 1 unit on both the axes.

  1. Plot the points A(1, 1), B(5, 3) and C(2, 7).
  2. Construct the locus of points equidistant from A and B.
  3. Construct the locus of points equidistant from AB and AC.
  4. Locate the point P such that PA = PB and P is equidistant from AB and AC.
  5. Measure and record the length PA in cm. 

Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB. 


Without using set squares or protractor, construct a quadrilateral ABCD in which ∠ BAD = 45°, AD = AB = 6 cm, BC= 3.6 cm and CD=5 cm. Locate the point P on BD which is equidistant from BC and CD. 


Construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm respectively. Find by construction a point P equidistant from AB and AD and also from C and D. 


Draw and describe the locus in the following case:

The locus of a point in rhombus ABCD which is equidistant from AB and AD.


Use ruler and compass only for the following question. All construction lines and arcs must be clearly shown.

  1. Construct a ΔABC in which BC = 6.5 cm, ∠ABC = 60°, AB = 5 cm.
  2. Construct the locus of points at a distance of 3.5 cm from A.
  3. Construct the locus of points equidistant from AC and BC.
  4. Mark 2 points X and Y which are at a distance of 3.5 cm from A and also equidistant from AC and BC. Measure XY.

Construct a Δ ABC, with AB = 6 cm, AC = BC = 9 cm; find a point 4 cm from A and equidistant from B and C.


Use ruler and compasses only for the following questions:
Construct triangle BCP, when CB = 5 cm, BP = 4 cm, ∠PBC = 45°.
Complete the rectangle ABCD such that :
(i) P is equidistant from AB and BC and
(ii) P is equidistant from C and D. Measure and write down the length of AB.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×