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Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm. Construct the locus of points equidistant from B and C - Mathematics

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प्रश्न

Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm.

  1. Construct the locus of points equidistant from B and C.
  2. Construct the locus of points equidistant from A and B.
  3. Mark the point which satisfies both the conditions (a) and (b) as 0. Construct the locus of points keeping a fixed distance OA from the fixed point 0.
  4. Construct the locus of points which are equidistant from BA and BC.
ज्यामितीय चित्र
लघु उत्तरीय
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उत्तर

  1. The locus of points equidistant from B and C is on BC's perpendicular bisector.
  2. Similarly, the locus will be at the perpendicular bisector of AB.
  3. The locus will be the circle that touches all three points, A, B, and C.
  4. The point equidistant from BA and BC will be the angle bisector of ∠ABC.
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अध्याय 14: Locus - Exercise 14 [पृष्ठ ३०३]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 14 Locus
Exercise 14 | Q 18. | पृष्ठ ३०३

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