मराठी

Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm. Construct the locus of points equidistant from B and C

Advertisements
Advertisements

प्रश्न

Use ruler and compass to answer this question. Construct ∠ABC = 90°, where AB = 6 cm, BC = 8 cm.

  1. Construct the locus of points equidistant from B and C.
  2. Construct the locus of points equidistant from A and B.
  3. Mark the point which satisfies both the conditions (a) and (b) as 0. Construct the locus of points keeping a fixed distance OA from the fixed point 0.
  4. Construct the locus of points which are equidistant from BA and BC.
भौमितिक रेखाचित्रे
लघु उत्तर
Advertisements

उत्तर

  1. The locus of points equidistant from B and C is on BC's perpendicular bisector.
  2. Similarly, the locus will be at the perpendicular bisector of AB.
  3. The locus will be the circle that touches all three points, A, B, and C.
  4. The point equidistant from BA and BC will be the angle bisector of ∠ABC.
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Locus - Exercise 14 [पृष्ठ ३०३]

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
पाठ 14 Locus
Exercise 14 | Q 18. | पृष्ठ ३०३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

O is a fixed point. Point P moves along a fixed line AB. Q is a point on OP produced such that OP = PQ. Prove that the locus of point Q is a line parallel to AB.


AB and CD are two intersecting lines. Find a point equidistant from AB and CD, and also at a distance of 1.8 cm from another given line EF. 


Draw and describe the lorus in  the following cases: 

The locus of points at a distance of 4 cm from a fixed line. 


Draw and describe the lorus in the following cases: 

The Iocus of the mid-points of all parallel chords of a circle.


Describe completely the locus of a point in the following case:

Midpoint of radii of a circle. 


Describe completely the locus of a point in the following case:

Centre of a circle of radius 2 cm and touching a fixed circle of radius 3 cm with centre O. 


Without using set squares or protractor construct a triangle ABC in which AB = 4 cm, BC = 5 cm and ∠ABC = 120°.
(i) Locate the point P such that ∠BAp = 90° and BP = CP.
(ii) Measure the length of BP.


Using only a ruler and compass construct ∠ABC = 120°, where AB = BC = 5 cm.
(i) Mark two points D and E which satisfy the condition that they are equidistant from both ABA and BC.
(ii) In the above figure, join AD, DC, AE and EC. Describe the figures:
(a) AECB, (b) ABD, (c) ABE.


How will you find a point equidistant from three given points A, B, C which are not in the same straight line?


Given ∠BAC (Fig), determine the locus of a point which lies in the interior of ∠BAC and equidistant from two lines AB and AC.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×