मराठी

Construct a triangle ABC, with AB = 5.6 cm, AC = BC = 9.2 cm. Find the points equidistant from AB and AC; and also 2 cm from BC.

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प्रश्न

Construct a triangle ABC, with AB = 5.6 cm, AC = BC = 9.2 cm. Find the points equidistant from AB and AC; and also 2 cm from BC. Measure the distance between the two points obtained. 

बेरीज
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उत्तर

 
Steps of construction:

  1. Draw a line segment AB = 5.6 cm
  2. From A and B, as centers and radius 9.2 cm, make two arcs which intersect each other at C.
  3. Join CA and CB.
  4. Draw two lines n and m parallel to BC at a distance of 2 cm
  5. Draw the angle bisector of ∠BAC which intersects m and n at P and Q respectively.
    P and Q are the required points which are equidistant from AB and AC.
    On measuring the distance between P and Q is 4.3 cm.
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पाठ 16: Loci (Locus and Its Constructions) - Exercise 16 (B) [पृष्ठ २४१]

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सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 16 Loci (Locus and Its Constructions)
Exercise 16 (B) | Q 23. | पृष्ठ २४१

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Use ruler and compasses only for this question:

I. Construct  ABC, where AB = 3.5 cm, BC = 6 cm and ABC = 60o.
II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
III. Construct the locus of points inside the triangle which are equidistant from B and C.
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