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प्रश्न
Using a ruler and compass only:
(i) Construct a triangle ABC with BC = 6 cm, ∠ABC = 120° and AB = 3.5 cm.
(ii) In the above figure, draw a circle with BC as diameter. Find a point 'P' on the circumference of the circle which is equidistant from Ab and BC.
Measure ∠BCP.
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उत्तर
(i) Steps of construction:
(1) Draw BC = 6 cm.
(2) Draw ∠ABC = 120°.
(3) Cut BA = 3·5 cm.
(4) Join A to C.
(5) Draw ⊥ bisector MN of BC.
(6) Draw a circle O as centre and OC, OB radius.
(7) Draw angle bisector of ∠ABC which intersect circle at P.
(ii) ∠BCP = 30°.
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संबंधित प्रश्न
Use ruler and compasses only for this question:
I. Construct ABC, where AB = 3.5 cm, BC = 6 cm and ABC = 60o.
II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
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IV. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and records the length of PB.
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Construct triangle BCP, when CB = 5 cm, BP = 4 cm, ∠PBC = 45°.
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