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प्रश्न
Construct a triangle ABC, with AB = 6 cm, AC = BC = 9 cm. Find a point 4 cm from A and equidistant from B and C.
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उत्तर
Steps of construction:
- Draw a line segment AB = 6 cm
- With A and B as centers and radius 9 cm, draw two arcs which intersect each other at C.
- Join AC and BC.
- Draw the perpendicular bisector of BC.
- With A as centre and radius 4 cm, draw an arc which intersects the perpendicular bisector of BC at P.
P is the required point which is equidistant from B and C and at a distance of 4 cm from A.
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संबंधित प्रश्न
Draw an angle ABC = 75°. Find a point P such that P is at a distance of 2 cm from AB and 1.5 cm from BC.
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Draw a straight line AB of 9 cm. Draw the locus of all points which are equidistant from A and B. Prove your statement.
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Using ruler and compasses construct:
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(ii) the locus of point equidistant from A and C.
(iii) a circle touching AB at A and passing through C.
Use ruler and compasses only for the following questions:
Construct triangle BCP, when CB = 5 cm, BP = 4 cm, ∠PBC = 45°.
Complete the rectangle ABCD such that :
(i) P is equidistant from AB and BC and
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