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Construct a triangle ABC, with AB = 6 cm, AC = BC = 9 cm. Find a point 4 cm from A and equidistant from B and C.

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प्रश्न

Construct a triangle ABC, with AB = 6 cm, AC = BC = 9 cm. Find a point 4 cm from A and equidistant from B and C. 

योग
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उत्तर

  
Steps of construction:

  1. Draw a line segment AB = 6 cm
  2. With A and B as centers and radius 9 cm, draw two arcs which intersect each other at C.
  3. Join AC and BC.
  4. Draw the perpendicular bisector of BC.
  5. With A as centre and radius 4 cm, draw an arc which intersects the perpendicular bisector of BC at P.
    P is the required point which is equidistant from B and C and at a distance of 4 cm from A.
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अध्याय 16: Loci (Locus and Its Constructions) - Exercise 16 (B) [पृष्ठ २४२]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 16 Loci (Locus and Its Constructions)
Exercise 16 (B) | Q 24. | पृष्ठ २४२

वीडियो ट्यूटोरियलVIEW ALL [1]

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