हिंदी

Using Only a Ruler and Compass Construct ∠Abc = 120°, Where Ab = Bc = 5 Cm. (I) Mark Two Points D and E Which Satisfy the Condition that They Are Equidistant from Both Aba and Bc. (Ii) in the Above - Mathematics

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प्रश्न

Using only a ruler and compass construct ∠ABC = 120°, where AB = BC = 5 cm.
(i) Mark two points D and E which satisfy the condition that they are equidistant from both ABA and BC.
(ii) In the above figure, join AD, DC, AE and EC. Describe the figures:
(a) AECB, (b) ABD, (c) ABE.

योग
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उत्तर

(i) and (ii)

(a) A quadrilateral
(b) A triangle
(c) A triangle.

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संबंधित प्रश्न

Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm and ∠BAC = 105°

Hence:

1) Construct the locus of points equidistant from BA and BC

2) Construct the locus of points equidistant from B and C.

3) Mark the point which satisfies the above two loci as P. Measure and write the length of PC.


Use ruler and compasses only for this question:

I. Construct  ABC, where AB = 3.5 cm, BC = 6 cm and ABC = 60o.
II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
III. Construct the locus of points inside the triangle which are equidistant from B and C.
IV. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and records the length of PB.


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