Advertisements
Advertisements
प्रश्न
In Δ PQR, s is a point on PR such that ∠ PQS = ∠ RQS . Prove thats is equidistant from PQ and QR.
Advertisements
उत्तर
Steps of Construction:
(i) Draw line segment PQ.
(ii) With P and Q as centre draw intersecting arcs at R.
(iii) Join PR and RQ.
(iv) Draw angle bisector of angle Q.
(v) Draw perpendicular bisectors of PQ and RQ which meet the angle bisector at S. S is the required point.
(vi) In Δ QSY and Δ QSX
SQ= SQ
∠ SQY = ∠ SQX
∠ SYQ = ∠ SXQ = 90 degrees.
Therefore, Δ QSY and Δ QSX are congruent.
Hence, SY = SX and therefore S is equidistant from PQ and RQ.
APPEARS IN
संबंधित प्रश्न
On a graph paper, draw the lines x = 3 and y = –5. Now, on the same graph paper, draw the locus of the point which is equidistant from the given lines.
Describe the locus of a point P, so that:
AB2 = AP2 + BP2,
where A and B are two fixed points.
State the locus of a point in a rhombus ABCD, which is equidistant
- from AB and AD;
- from the vertices A and C.
Use ruler and compasses only for this question. Draw a circle of radius 4 cm and mark two chords AB and AC of the circle of lengths 6 cm and 5 cm respectively.
(i) Construct the locus of points, inside the circle, that are equidistant from A and C. prove your construction.
(ii) Construct the locus of points, inside the circle that are equidistant from AB and AC.
Draw two intersecting lines to include an angle of 30°. Use ruler and compasses to locate points which are equidistant from these Iines and also 2 cm away from their point of intersection. How many such points exist?
Construct a rhombus ABCD with sides of length 5 cm and diagonal AC of length 6 cm. Measure ∠ ABC. Find the point R on AD such that RB = RC. Measure the length of AR.
In the given figure ABC is a triangle. CP bisects angle ACB and MN is perpendicular bisector of BC. MN cuts CP at Q. Prove Q is equidistant from B and C, and also that Q is equidistant from BC and AC.
In given figure, ABCD is a kite. AB = AD and BC =CD. Prove that the diagona AC is the perpendirular bisector of the diagonal BD.
State and draw the locus of a swimmer maintaining the same distance from a lighthouse.
Without using set squares or protractor.
(i) Construct a ΔABC, given BC = 4 cm, angle B = 75° and CA = 6 cm.
(ii) Find the point P such that PB = PC and P is equidistant from the side BC and BA. Measure AP.
