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Construct a Fixyz in Which Xy= 4 Cm, Yz = 5 Cm and L.Y = 1200. - Mathematics

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प्रश्न

Construct a Δ XYZ in which XY= 4 cm, YZ = 5 cm and ∠ Y = 1200. Locate a point T such that ∠ YXT is a right angle and Tis equidistant from Y and Z. Measure TZ. 

आकृति
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उत्तर

Steps of Construction: 

(i) Draw YZ = 5 cm 

(ii) Draw an arc with angle Y= 120 ° and radius 4 cm. 

(iii) Join XZ. 

(iv) Draw perpendicular bisector of YZ. 

(v) With X as centre and angle X as 90° , join X to the perpendicular bisectcr at T. T is the required point. 

(vi) Measure TY. TY = 6.8 cm = TZ as T lies on perpendicular bisector of YZ. 

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अध्याय 16: Loci - Exercise 16.1

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 16 Loci
Exercise 16.1 | Q 9

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