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Question
Construct a Δ XYZ in which XY= 4 cm, YZ = 5 cm and ∠ Y = 1200. Locate a point T such that ∠ YXT is a right angle and Tis equidistant from Y and Z. Measure TZ.
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Solution
Steps of Construction:
(i) Draw YZ = 5 cm
(ii) Draw an arc with angle Y= 120 ° and radius 4 cm.
(iii) Join XZ.
(iv) Draw perpendicular bisector of YZ.
(v) With X as centre and angle X as 90° , join X to the perpendicular bisectcr at T. T is the required point.
(vi) Measure TY. TY = 6.8 cm = TZ as T lies on perpendicular bisector of YZ.
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