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प्रश्न
Construct a rhombus ABCD with sides of length 5 cm and diagonal AC of length 6 cm. Measure ∠ ABC. Find the point R on AD such that RB = RC. Measure the length of AR.
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उत्तर
Steps of Construction:
(i) Draw AC= 6 cm.
(ii) With A as centre, draw two arcs of 5 cm on both sides of line AC.
(iii) With C as centre, draw two arcs of 5 cm on both sides of line AC.
(iv) All the arcs meet at Band D. Join AB, AD, BC and BD. ABCD is the required rhombus.
(v) On measuring, ∠ ABC = 78>.
(vi) Draw perpendicular bisector of BC meeting AD at R. R is the pdnt equidistant from Band C, hence RB = RC.
(vii) On measuring, R = 1.2 cm
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संबंधित प्रश्न
Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm and ∠BAC = 105°
Hence:
1) Construct the locus of points equidistant from BA and BC
2) Construct the locus of points equidistant from B and C.
3) Mark the point which satisfies the above two loci as P. Measure and write the length of PC.
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