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प्रश्न
Using only ruler and compasses, construct a triangle ABC 1 with AB = 5 cm, BC = 3.5 cm and AC= 4 cm. Mark a point P, which is equidistant from AB, BC and also from Band C. Measure the length of PB.
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उत्तर
Steps of construction:
(i) Draw a line segment BC = 3. 5 cm.
(ii) With Bas centre and radius 5 cm draw an arc.
(iii) With C as centre and radius 4 cm draw another arc which intersects the first arc at A.
(iv) Join AB and AC.
(v) Dr aw perpendi cu I ar bi sector of BC.
(vi) Dr aw the angle bi sector of angle ABC which intersects the perpendicular bisector of BC at P.
Pis the required point which is equidistant from AB, BC, Band C.
The length of PB = 2.5 cm
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संबंधित प्रश्न
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Ruler and compass only may be used in this question. All construction lines and arcs must be clearly shown, and be of sufficient length and clarity to permit assessment.
(i) Construct Δ ABC, in which BC = 8 cm, AB = 5 cm, ∠ ABC = 60°.
(ii) Construct the locus of point inside the triangle which are equidistant from BA and BC.
(iii) Construct the locus of points inside the triangle which are equidistant from B and C.
(iv) Mark as P, the point which is equidistant from AB, BC and also equidistant from B and C.
(v) Measure and record the length of PB.
