मराठी

Without Using Set Squares Or Protractor, Construct a Quadrilateral Abcd in Which Lbad = 45° 1 Ad=Ab=6 Cm, Bc=3.6 Cm and Cd=S Cm. - Mathematics

Advertisements
Advertisements

प्रश्न

Without using set squares or protractor, construct a quadrilateral ABCD in which ∠ BAD = 45°, AD = AB = 6 cm, BC= 3.6 cm and CD=5 cm. Locate the point P on BD which is equidistant from BC and CD. 

Without using set squares or protractor, construct a quadrilateral ABCD in which ∠ BAD = 45°, AD = AB = 6 cm, BC = 3.6 cm and CD = 5 cm.

  1. Measure ∠BCD
  2. Locate point P on BD which is equidistant from BC and CD.
भौमितिक रेखाचित्रे
दीर्घउत्तर
सविस्तर उत्तर
Advertisements

उत्तर १

Steps of construction:

  1. Draw a line AB = 6 cm. 
  2. Draw a ray making an angle of 45° with AB. 
  3. With A as the centre, draw AD = 6 cm on the ray. 
  4. Draw an angle bisector of angle BAD. 
  5. With B as the centre, cut an arc BC = 3.6 cm on the angle bisector. 
  6. With Das, centre cut an arc CD = 5 cm on the angle bisector. ABCD is the required quadrilateral. 
  7. Join BD. 
  8. Draw perpendicular bisectors of CD and BC which meet BD at P. P is the required point. 
shaalaa.com

उत्तर २

  1. ∠BCD = 62°.
  2. Draw the angle bisector of ∠BCD. Join BD.
    The point of intersection of the bisector and BD is P. P is equidistant from BC and CD.
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Loci - Exercise 16.1

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
पाठ 14 Locus
Exercise 14 | Q 13. | पृष्ठ ३०३

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

On a graph paper, draw the line x = 6. Now, on the same graph paper, draw the locus of the point which moves in such a way that its distantce from the given line is always equal to 3 units 


Describe the locus of a point P, so that:

AB2 = AP2 + BP2,

where A and B are two fixed points.


Draw an angle ABC = 75°. Find a point P such that P is at a distance of 2 cm from AB and 1.5 cm from BC.


State the locus of a point in a rhombus ABCD, which is equidistant

  1. from AB and AD;
  2. from the vertices A and C.

Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB. 


Draw two intersecting lines to include an angle of 30°. Use ruler and compasses to locate points which are equidistant from these Iines and also 2 cm away from their point of intersection. How many such points exist? 


Construct a ti.PQR, in which PQ=S. 5 cm, QR=3. 2 cm and PR=4.8 cm. Draw the locus of a point which moves so that it is always 2.5 cm from Q. 


Construct a triangle ABC, such that AB= 6 cm, BC= 7.3 cm and CA= 5.2 cm. Locate a point which is equidistant from A, B and C.


Use ruler and compass only for the following question. All construction lines and arcs must be clearly shown.

  1. Construct a ΔABC in which BC = 6.5 cm, ∠ABC = 60°, AB = 5 cm.
  2. Construct the locus of points at a distance of 3.5 cm from A.
  3. Construct the locus of points equidistant from AC and BC.
  4. Mark 2 points X and Y which are at a distance of 3.5 cm from A and also equidistant from AC and BC. Measure XY.

Using only a ruler and compass construct ∠ABC = 120°, where AB = BC = 5 cm.
(i) Mark two points D and E which satisfy the condition that they are equidistant from both ABA and BC.
(ii) In the above figure, join AD, DC, AE and EC. Describe the figures:
(a) AECB, (b) ABD, (c) ABE.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×