मराठी

Describe completely the locus of a point in the following case: Midpoint of radii of a circle.

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प्रश्न

Describe completely the locus of a point in the following case:

Midpoint of radii of a circle. 

अति संक्षिप्त उत्तर
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उत्तर

The locus of mid-point of the radii of a circle is a concentric circle of radius equal to half the radius of the given circle. 

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पाठ 14: Locus - Exercise 14 [पृष्ठ ३०२]

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
पाठ 14 Locus
Exercise 14 | Q 1. (i) | पृष्ठ ३०२
फ्रँक Mathematics Part 2 [English] Class 10 ICSE
पाठ 15 Loci
Exercise 16.1 | Q 24.1

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:

  1. equidistant from BA and BC.
  2. 4 cm from M.
  3. 4 cm from N.
    Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Join MP and NP, and describe the figure BMPN.

Draw an angle ABC = 75°. Find a point P such that P is at a distance of 2 cm from AB and 1.5 cm from BC.


Construct a triangle ABC, with AB = 6 cm, AC = BC = 9 cm. Find a point 4 cm from A and equidistant from B and C. 


Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB. 


Two straight roads AB and CD cross each other at Pat an angle of 75°  . X is a stone on the road AB, 800m from P towards B. BY taking an appropriate scale draw a figure to locate the position of a pole, which is equidistant from P and X, and is also equidistant from the roads. 


Construct a ti.PQR, in which PQ=S. 5 cm, QR=3. 2 cm and PR=4.8 cm. Draw the locus of a point which moves so that it is always 2.5 cm from Q. 


In given figure 1 ABCD is an arrowhead. AB = AD and BC = CD. Prove th at AC produced bisects BD at right angles at the point M


Describe completely the locus of a point in the following case:

Point in a plane equidistant from a given line. 


Without using set squares or a protractor, construct:

  1. Triangle ABC, in which AB = 5.5 cm, BC = 3.2 cm and CA = 4.8 cm.
  2. Draw the locus of a point which moves so that it is always 2.5 cm from B.
  3. Draw the locus of a point which moves so that it is equidistant from the sides BC and CA.
  4. Mark the point of intersection of the loci with the letter P and measure PC.

How will you find a point equidistant from three given points A, B, C which are not in the same straight line?


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