English

Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is: equidistant from BA and BC. 4 cm from M. 4 cm from N.

Advertisements
Advertisements

Question

Angle ABC = 60° and BA = BC = 8 cm. The mid-points of BA and BC are M and N respectively. Draw and describe the locus of a point which is:

  1. equidistant from BA and BC.
  2. 4 cm from M.
  3. 4 cm from N.
    Mark the point P, which is 4 cm from both M and N, and equidistant from BA and BC. Join MP and NP, and describe the figure BMPN.
Sum
Advertisements

Solution

  

  1. Draw an angle of 60° with AB = BC = 8 cm
  2. Draw the angle bisector BX of ∠ABC
  3. With centre M and N, draw circles of radius equal to 4 cm, which intersects each other at P. P is the required point.
  4. Join MP, NP
    BMPN is a rhombus since MP = BM = NB = NP = 4 cm 
shaalaa.com
  Is there an error in this question or solution?
Chapter 16: Loci (Locus and Its Constructions) - Exercise 16 (B) [Page 241]

APPEARS IN

Selina Concise Mathematics [English] Class 10 ICSE
Chapter 16 Loci (Locus and Its Constructions)
Exercise 16 (B) | Q 19. | Page 241

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Construct a triangle ABC with AB = 5.5 cm, AC = 6 cm and ∠BAC = 105°

Hence:

1) Construct the locus of points equidistant from BA and BC

2) Construct the locus of points equidistant from B and C.

3) Mark the point which satisfies the above two loci as P. Measure and write the length of PC.


Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB. 


AB and CD are two intersecting lines. Find a point equidistant from AB and CD, and also at a distance of 1.8 cm from another given line EF. 


Construct a rhombus ABCD whose diagonals AC and BD are 8 cm and 6 cm respectively. Find by construction a point P equidistant from AB and AD and also from C and D. 


A and B are fixed points while Pis a moving point, moving in a way that it is always equidistant from A and B. What is the locus of the path traced out by the pcint P? 


In given figure, ABCD is a kite. AB = AD and BC =CD. Prove that the diagona AC is the perpendirular bisector of the diagonal BD. 


State and draw the locus of a swimmer maintaining the same distance from a lighthouse.


Construct a Δ ABC, with AB = 6 cm, AC = BC = 9 cm; find a point 4 cm from A and equidistant from B and C.


Using a ruler and compass only: 
(i) Construct a triangle ABC with BC = 6 cm, ∠ABC = 120° and AB = 3.5 cm.
(ii) In the above figure, draw a circle with BC as diameter. Find a point 'P' on the circumference of the circle which is equidistant from Ab and BC.
Measure ∠BCP.


Use ruler and compasses only for this question. Draw a circle of radius 4 cm and mark two chords, AB and AC, of the circle of length 6 cm and 5 cm respectively.

  1. Construct the locus of points, inside the circle, that are equidistant from A and C. Prove your construction.
  2. Construct the locus of points, inside the circle, that are equidistant from AB and AC.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×