English

Describe the locus of vertices of all isosceles triangles having a common base. - Mathematics

Advertisements
Advertisements

Questions

Describe the locus of vertices of all isosceles triangles having a common base.

Draw and describe the locus in the following case:

The locus of vertices of all isosceles triangles having a common base.

Diagram
Very Short Answer
Advertisements

Solution

The locus of vertices of all isosceles triangles having a common base will be the perpendicular bisector of the common base of the triangles.

shaalaa.com
  Is there an error in this question or solution?
Chapter 14: Locus - Exercise 14 [Page 302]

APPEARS IN

Nootan Mathematics [English] Class 10 ICSE
Chapter 14 Locus
Exercise 14 | Q 2. (ii) | Page 302

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Describe the locus of a point in space, which is always at a distance of 4 cm from a fixed point.  


Describe the locus of a point P, so that:

AB2 = AP2 + BP2,

where A and B are two fixed points.


Construct a triangle ABC, with AB = 5.6 cm, AC = BC = 9.2 cm. Find the points equidistant from AB and AC; and also 2 cm from BC. Measure the distance between the two points obtained. 


State the locus of a point in a rhombus ABCD, which is equidistant

  1. from AB and AD;
  2. from the vertices A and C.

Construct a Δ XYZ in which XY= 4 cm, YZ = 5 cm and ∠ Y = 1200. Locate a point T such that ∠ YXT is a right angle and Tis equidistant from Y and Z. Measure TZ. 


Draw and describe the locus in the following case:

The locus of points inside a circle and equidistant from two fixed points on the circle.


Draw and describe the locus in the following case:

The locus of a point in rhombus ABCD which is equidistant from AB and AD.


Describe completely the locus of a point in the following case:

Midpoint of radii of a circle. 


Draw and describe the locus in the following case:

The locus of a point in the rhombus ABCD which is equidistant from the point  A and C.


Without using set squares or a protractor, construct:

  1. Triangle ABC, in which AB = 5.5 cm, BC = 3.2 cm and CA = 4.8 cm.
  2. Draw the locus of a point which moves so that it is always 2.5 cm from B.
  3. Draw the locus of a point which moves so that it is equidistant from the sides BC and CA.
  4. Mark the point of intersection of the loci with the letter P and measure PC.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×