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Question
Calculate the molarity of the following solution:
30 mL of 0.5 M H2SO4 diluted to 500 mL.
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Solution
Number of moles present in 500 mL of 0.5 M H2SO4 = 0.5 mol
∴ V1 = 30 mL
M1 = 0.5 M
V2 = 500 mL
M2 = ?
Using the formula:
M1V1 = M2V2
⇒ 0.5 M × 30 mL = M2 × 500 mL
⇒ M2 = `(0.5 xx 30)/500`
⇒ `15/500`
⇒ 0.03 M
∴ The molarity of the solution is 0.03 M.
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