Question

The number of electrons involved in the reduction of one nitrate ion to hydrazine is

Options

• 8

• 5

• 3

• 7

Answer 1

7

Explanation:

\[\ce{\underset{+5}{N}O^{-}3 -> \underset{-2}{N}2H4}\] So, for reduction of 1 mole of \[\ce{NO^{-}3}\], number of electrons required is 7.