English
Karnataka Board PUCPUC Science 2nd PUC Class 12

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ______.

Advertisements
Advertisements

Question

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ______.

Options

  • 0.004

  • 0.008

  • 0.012

  • 0.016

MCQ
Fill in the Blanks
Advertisements

Solution

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is 0.016.

Explanation:

Apply the relation: M1V1 = M2V2 

Given: M1 = 0.02 M, V1 = 4 L, M2 = ?, V2 = 5 L

Therefore 0.02 × 4 L = M2 × 5 L

M2 = `0.08/5` = 0.016 M

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Solutions - Exercises [Page 21]

APPEARS IN

NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 2 Solutions
Exercises | Q I. 24. | Page 21

RELATED QUESTIONS

Define mole fraction.


How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 containing equimolar amounts of both?


If the density of some lake water is 1.25 g mL−1 and contains 92 g of Na+ ions per kg of water, calculate the molality of Na+ ions in the lake.


When KOH solution is added to potassium dichromate solution the colour of solution
changes to yellow, because _______

(A) chromate ion changes to dichromate ion

(B) dichromate ion changes to chromate ion

(C) oxidation number of chromium changes from + 6 to + 4

(D) oxidation number of chromium changes from + 4 to +6


Which of the following is a quantitative description of the solution?


4.0 g of NaOH is dissolved in 100 ml solution. The normality of the solution is ____________.


How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0M HNO3? The concentrated acid is 70% HNO3:


A solution is prepared by dissolving 10 g NaOH in 1250 mL of a solvent of density 0.8 mL/g. The molality of the solution in mol kg–1 is:


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Molarity of a solution changes with temperature.

Reason (R): Molarity is a colligative property.

Select the most appropriate answer from the options given below:


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

x (mole fraction)


Match List-I with List-II:

List-I List-II
A. ppm I. molL-¹
B. Molarity II. No units
C. Molality III. Independent of temperature
D. Mole fraction IV. Very dilute solutions

Choose the correct answer from the options given below:


The number of electrons involved in the reduction of one nitrate ion to hydrazine is


What is molarity of resulting solution obtained by mixing 8.5 L of 0.5 m urea solution and 500 ml of 2 m urea solution?


Calculated the mole fraction of benzene in a solution containing 30% by mass of its is carbon tetrachloride


Calculate the mass percent of benzene (CoH6) and carbon tetrachloride (ccl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.


138 g ethyl alcohol is mixed with 72 g of water. The ratio of mole fraction of alcohol to water is ______.


250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is ______ × 1021. (Nearest integer) (NA = 6.022 × 1023).


The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4 · 2 H2O) in 250 mL of water in mol L-1 is x × 10-2. The value of x is ______. (Nearest integer)

[Atomic mass: H : 1.0, C : 12.0, O : 16.0]


A 5% solution of \[\ce{Na2SO4.10H2O}\] (MW = 3 22) is isotonic with 2% solution of non- electrolytic, non volatile substance X. Find out the molecular weight of X.


Calculate the molarity of the following solution:

30 mL of 0.5 M H2SO4 diluted to 500 mL.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×