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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ______.

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प्रश्न

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ______.

विकल्प

  • 0.004

  • 0.008

  • 0.012

  • 0.016

MCQ
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उत्तर

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is 0.016.

Explanation:

Apply the relation: M1V1 = M2V2 

Given: M1 = 0.02 M, V1 = 4 L, M2 = ?, V2 = 5 L

Therefore 0.02 × 4 L = M2 × 5 L

M2 = `0.08/5` = 0.016 M

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अध्याय 2: Solutions - Exercises [पृष्ठ २१]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 2 Solutions
Exercises | Q I. 24. | पृष्ठ २१

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