English
Karnataka Board PUCPUC Science 2nd PUC Class 12

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

Advertisements
Advertisements

Question

A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.

Numerical
Advertisements

Solution

300 g of 25% solution contains solute = 75 g

400 g of 40% solution contains solute = 160 g

Total solute = 160 + 75 = 235 g

Total solution = 300 + 400 = 700 g

% of solute in the final solution = `235/700 xx 100`

= 33.5%

% of water in the final solution = 100 − 33.5

= 66.5%

shaalaa.com
  Is there an error in this question or solution?
Chapter 1: Solutions - Exercises [Page 28]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 1 Solutions
Exercises | Q 1.7 | Page 28
Nootan Chemistry [English] Class 12 ISC
Chapter 1 Solutions
'NCERT TEXT-BOOK' Exercises | Q 2.7 | Page 124

RELATED QUESTIONS

Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution.


Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of such a sample of the acid if the density of the solution is 1.504 g mL−1?


How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 containing equimolar amounts of both?


5 ml of N HCl, 20 ml of N/2 H2SO4 and 30 ml of N/3 HNO3 are mixed together and volume made to one litre. The normality of the resulting solution is:


Mole fraction of the solute in a 1.00 molal aqueous solution is ____________.


If N/10 50 ml H2SO4, N/3 30 ml HNO3, N/2 10 ml HCl is mixed and solution is made to 1 L. Then normality of the resultant solution is:


4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ______.


Cone. H2SO4 is 98% H2SO4 by mass has d = 1.84 g cm−3. Volume of acid required to make one litre of 0.1 M H2SO4 is:


What is the mole fraction of solute in 1.00 m aqueous solutions?


Which of the following is a correct statement for C2H5Br?


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Molarity of a solution changes with temperature.

Reason (R): Molarity is a colligative property.

Select the most appropriate answer from the options given below:


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

w/w (mass percentage)


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

V/V (volume percentage)


Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?

(iii) w/V (mass by volume percentage)


Calculated the mole fraction of benzene in a solution containing 30% by mass of its is carbon tetrachloride


Calculate the mass percent of benzene (CoH6) and carbon tetrachloride (ccl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.


138 g ethyl alcohol is mixed with 72 g of water. The ratio of mole fraction of alcohol to water is ______.


A 6.50 molal solution of KOH (aq.) has a density of 1.89 g cm−3. The molarity of the solution is ______ mol dm−3. (Round off to the Nearest Integer)

[Atomic masses: K: 39.0 u; O: 16.0 u; H: 1.0 u]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×