Advertisements
Advertisements
प्रश्न
Calculate the molarity of the following solution:
30 mL of 0.5 M H2SO4 diluted to 500 mL.
Advertisements
उत्तर
Number of moles present in 500 mL of 0.5 M H2SO4 = 0.5 mol
∴ V1 = 30 mL
M1 = 0.5 M
V2 = 500 mL
M2 = ?
Using the formula:
M1V1 = M2V2
⇒ 0.5 M × 30 mL = M2 × 500 mL
⇒ M2 = `(0.5 xx 30)/500`
⇒ `15/500`
⇒ 0.03 M
∴ The molarity of the solution is 0.03 M.
APPEARS IN
संबंधित प्रश्न
Calculate the molarity of the following solution:
30 g of Co(NO3)2 . 6H2O in 4.3 L of solution.
Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5 × 10−3 m aqueous solution required for the above dose.
When KOH solution is added to potassium dichromate solution the colour of solution
changes to yellow, because _______
(A) chromate ion changes to dichromate ion
(B) dichromate ion changes to chromate ion
(C) oxidation number of chromium changes from + 6 to + 4
(D) oxidation number of chromium changes from + 4 to +6
Define molality.
Define Normality.
When a solute is present in trace quantities the following expression is used:
Mole fraction of the solute in a 1.00 molal aqueous solution is ____________.
The volume of 4 N HCl and 10 N HCl required to make 1 litre of 6 N HCl are ____________.
What is the mole fraction of solute in 1.00 m aqueous solutions?
Given below are two statements labelled as Assertion (A) and Reason (R).
Assertion (A): Molarity of a solution changes with temperature.
Reason (R): Molarity is a colligative property.
Select the most appropriate answer from the options given below:
Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?
w/w (mass percentage)
Define the following modes of expressing the concentration of a solution. Which of these modes are independent of temperature and why?
ppm. (parts per million)
The number of electrons involved in the reduction of one nitrate ion to hydrazine is
What is the normality of 0.3 m H3Pcl solution?
4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10−1. The value of x is ______. (Rounded-off to the nearest integer)
250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is ______ × 1021. (Nearest integer) (NA = 6.022 × 1023).
A given solution of H2O2 is 30 volumes. Its concentration in terms of molarity is ______.
The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4 · 2 H2O) in 250 mL of water in mol L-1 is x × 10-2. The value of x is ______. (Nearest integer)
[Atomic mass: H : 1.0, C : 12.0, O : 16.0]
4 ml of pure A (d = 2.45 gm/ml) was added to 46 ml of B (d = `25.1/23` gm/ml), the molarity of a solution of A in B will be ______, if the density of the final solution is 1.8 gm/ml.
Given: Molar mass of A = 98, Molar mass of B = 46
