मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Calculate the molarity of the following solution: 30 mL of 0.5 M H2SO4 diluted to 500 mL.

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प्रश्न

Calculate the molarity of the following solution:

30 mL of 0.5 M H2SO4 diluted to 500 mL.

संख्यात्मक
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उत्तर

Number of moles present in 500 mL of 0.5 M H2SO4 = 0.5 mol

∴ V1 = 30 mL

M1 = 0.5 M

V2 = 500 mL

M2 = ?

Using the formula:

M1V1 = M2V2

⇒ 0.5 M × 30 mL = M2 × 500 mL

⇒ M2 = `(0.5 xx 30)/500`

⇒ `15/500`

⇒ 0.03 M

∴ The molarity of the solution is 0.03 M.

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पाठ 1: Solutions - Intext Questions [पृष्ठ ५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 1 Solutions
Intext Questions | Q 1.3 (b) | पृष्ठ ५

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